javascript - Regex to find pattern, return subpattern -

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 var s = "lala url(ok) tee hee url( oh ya ) kk";  s.match( /url(([^)]+))/g );

from 's' trying extract:

 ['ok', ' oh ya ']

but, getting:

 ["url(ok", "url( oh ya "]

i can iterate on list , remove 'url(', suspect regex-fu can remove too.

in other language regex support lookbehind using regex (?<=url\()(([^)]+))

but unfortunately javascript regex doesn't support lookbehind this example, must iterate it. except don't realy need url word included.


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