oracle - Extract text between words -

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i trying extract numbers between 2 words distincts, "substr" don't work combined "instr". @ least i'm not getting!

example:

codtax  tax_description ----------------------- 1225    ncm 85444900 ipi 0% icms 18% cst 060 iva 41,00% iva ext 51,32%

the extract number between "ipi " , "% icms" 0 or between "iva " , "% iva" 41.00.

create table tax (   codtax           number,   tax_description  varchar2(200 byte) );  insert tax (codtax, tax_description)      values (1505, 'ncm 29051220 ipi 0% icms 18% cst 000 iva 0% iva ext 0%'); insert tax  (codtax, tax_description)       values (1258, 'ncm 85444900 ipi 0% icms 18% cst 060 iva 41,00% iva ext 51,32%'); insert tax (codtax, tax_description)      values (2051, 'ncm 85362000 ipi 10% icms 18% cst 060 iva 43,00% iva ext 53,46%');

the result must be: 

codtax  tax_description                                                 ipi    iva ---------------------------------------------------------------------------------- 1505    ncm 29051220 ipi 0% icms 18% cst 000 iva 0% iva ext 0%            0      0  1258    ncm 85444900 ipi 0% icms 18% cst 060 iva 41,00% iva ext 51,32%    0  41,00  2051    ncm 85362000 ipi 10% icms 18% cst 060 iva 43,00% iva ext 53,46%  10  43,00

you can try combination of instr , regexp_substr.

select a.*,        regexp_substr (a.tax_description,                       '\d+,?\d*',                       instr (a.tax_description, 'ipi')) ipi,        regexp_substr (a.tax_description,                       '\d+,?\d*',                       instr (a.tax_description, 'iva')) iva   tax a;

instr used find first position of ipi , iva. used in regexp_substr function specify starting position.

the regex pattern,

  • \d+ matches 1 or more digits.
  • ,? matches 0 or 1 comma.
  • \d* matches 0 or more digits.

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