php - form select with ajax -

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i'm building bug tracker tool.

when create project, can change project status (open, in progress & finished) on project page using select form:

    <form action="classes/projectstatus.class.php" method="post">           <label> change project status </label>           <select name="status" id="status">                <option value="open">open</option>                <option value="in progress">in progress</option>                <option value="finished">finished</option>            </select>            <input type='hidden' name='hdnid' value="<?php echo $id;?>">             <input class="small button" value="change status" type="submit">      </form>

this projectstatus.class.php file:

 $status = $_post['status'];  $id     = $_post['hdnid'];  $sql="update projects set status = '$status'";     $result = mysql_query($sql);   $result = mysql_real_escape_string($sql);    if($result){       header('location: ../projectpage.php?id='.$id);        } else {        echo "there wrong. try again later."; }        mysql_close();

how can ajax? provide me right code?!

i know form isn't sql injection proof , don't use mysqli, change this, first i'd have answer :).

thanks!

i use jquery, solve lot of compatibility issues.

there example code here on jquery site: http://api.jquery.com/jquery.post/


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