logic - Is break; required after die() php -
i've been thinking much...
in area of switch case break;
required after die()
example:
switch($i){ case 0: die('case without break;'); case 1: die('case break;'); break; }
die()
alias exit()
, exit() terminate program flow immediately. (shutdown functions , object destructors still executed after exit()
)
and no, not syntax error omit break
, on contrary there many useful cases omitting break
. check manual page of switch
statement examples.
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