Determine where PHP is exiting using code, not debugger -

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i cannot figure out application exiting. i'd rather not bother debugger, , adding declare(ticks=1); each file pain (i'm not in mood dealing sed). similar question has been asked, not these constraints.

how can figure out code exiting?

clarification:

while question similar fastest way determine php script exits, i'd find solution works without debugger. know how debugger, don't have access such tools.

you don't need add declare(ticks) files. 1 entry point enough:

<?php function my_tick() {     echo 'tick'; }  register_tick_function('my_tick'); declare (ticks=1) {     include("lib.php");     echo "1";     test(); }

and lib.php:

<?php  echo "2";  function test(){    echo "3";  }

and looking code-based solution assume sources provide single entry point.


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