c - what is output ? gcc output is 0. please explain? -

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this question has answer here:

gcc compiler output 0. why? shouldn't 3? 

int main() {     f(3);     return 0; }  int f(int t) {     int c;      switch(t)     {     case 2:         c=2;     case 3:         c=3;     case 4:         c=4;     case 5:         c=5;     default:         c=0;     }     printf("%d",c); }

because missing break; statement in each of cases. leads control falling through following case statements , default case.


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